Remove space-padding from <pre> blocks

6 files changed, 12 insertions, 12 deletions

diff --git a/prolog/problems/dcg/expr_3/en.py b/prolog/problems/dcg/expr_3/en.py
index 298ebeb..f853ad2 100644
--- a/prolog/problems/dcg/expr_3/en.py
+++ b/prolog/problems/dcg/expr_3/en.py
@@ -7,8 +7,8 @@ description = '''\
 <p>Write a DCG with the starting symbol <code>expr</code> for the language of arithmetic expressions consisting of numbers (without leading zeros), addition and multiplication. Subexpressions can be grouped using parentheses. The meaning of a word in this language is the numeric value of the represented arithmetic expression.</p>
 <p>Example words: <code>(1+2)*3</code>, <code>42*8*3</code>, <code>(2+1)*(3+4)</code>.</p>
 <pre>
-  ?- expr(N, ['(',2,'+',1,')','*','(',3,'+',4,')'], []).  % (2+1)*(3+4) = 21
-    N = 21.
+?- expr(N, ['(',2,'+',1,')','*','(',3,'+',4,')'], []).  % (2+1)*(3+4) = 21
+  N = 21.
 </pre>
 '''
 
diff --git a/prolog/problems/dcg/expr_3/sl.py b/prolog/problems/dcg/expr_3/sl.py
index 734a6ea..23fed26 100644
--- a/prolog/problems/dcg/expr_3/sl.py
+++ b/prolog/problems/dcg/expr_3/sl.py
@@ -7,8 +7,8 @@ description = '''\
 <p>Napiši gramatiko z začetnim simbolom <code>expr</code> za jezik aritmetičnih izrazov, ki vsebujejo števila (brez vodilnih ničel), vsoto in množenje. Podizrazi se lahko združujejo z oklepaji. Pomen besede v tem jeziku je numerična vrednost predstavljenega izraza.</p>
 <p>Primeri veljavnih besed: <code>(1+2)*3</code>, <code>42*8*3</code>, <code>(2+1)*(3+4)</code>.</p>
 <pre>
-  ?- expr(N, ['(',2,'+',1,')','*','(',3,'+',4,')'], []).  % (2+1)*(3+4) = 21
-    N = 21.
+?- expr(N, ['(',2,'+',1,')','*','(',3,'+',4,')'], []).  % (2+1)*(3+4) = 21
+  N = 21.
 </pre>
 '''
 
diff --git a/prolog/problems/dcg/number_3/en.py b/prolog/problems/dcg/number_3/en.py
index c2f9c3d..6516db7 100644
--- a/prolog/problems/dcg/number_3/en.py
+++ b/prolog/problems/dcg/number_3/en.py
@@ -6,8 +6,8 @@ slug = 'numbers with meaning'
 description = '''\
 <p>Write a DCG with the starting symbol <code>number</code> for the language of non-negative integers. The numbers may contain leading zeros. The meaning of a word in this language is the numeric value of the represented number.</p>
 <pre>
-  ?- number(N, [1,2,3,4], []).
-    N = 1234.
+?- number(N, [1,2,3,4], []).
+  N = 1234.
 </pre>
 '''
 
diff --git a/prolog/problems/dcg/number_3/sl.py b/prolog/problems/dcg/number_3/sl.py
index eeb4db2..bcb2cf4 100644
--- a/prolog/problems/dcg/number_3/sl.py
+++ b/prolog/problems/dcg/number_3/sl.py
@@ -6,8 +6,8 @@ slug = 'Števila s pomenom'
 description = '''\
 <p>Napiši gramatiko z začetnim simbolom <code>number</code> za jezik nenegativnih celih števil. Števila lahko vsebujejo vodilne ničle. Pomen besede v tem jeziku je kar numerična vrednost predstavljenega števila.</p>
 <pre>
-  ?- number(N, [1,2,3,4], []).
-    N = 1234.
+?- number(N, [1,2,3,4], []).
+  N = 1234.
 </pre>
 '''
 
diff --git a/prolog/problems/dcg/paren_3/en.py b/prolog/problems/dcg/paren_3/en.py
index 56519ff..4a8e0a8 100644
--- a/prolog/problems/dcg/paren_3/en.py
+++ b/prolog/problems/dcg/paren_3/en.py
@@ -6,8 +6,8 @@ slug = 'properly nested parens with meaning'
 description = '''\
 <p>Write a DCG with the starting symbol <code>paren</code> for the language of properly nested sequences of parentheses. The meaning of a word in this language is the maximum depth of the nested parentheses.</p>
 <pre>
-  ?- paren(D, ['(','(',')',')','(',')'], []).  % (())()
-    D = 2.
+?- paren(D, ['(','(',')',')','(',')'], []).  % (())()
+  D = 2.
 </pre>
 '''
 
diff --git a/prolog/problems/dcg/paren_3/sl.py b/prolog/problems/dcg/paren_3/sl.py
index a98eb8b..d721506 100644
--- a/prolog/problems/dcg/paren_3/sl.py
+++ b/prolog/problems/dcg/paren_3/sl.py
@@ -6,8 +6,8 @@ slug = 'Pravilno gnezdeni oklepaji s pomenom'
 description = '''\
 <p>Napiši gramatiko z začetnim simbolom <code>paren</code> za jezik pravilno gnezdenih zaporedij oklepajev. Pomen besede v tem jeziku je največja globina gnezdenja oklepajev.</p>
 <pre>
-  ?- paren(D, ['(','(',')',')','(',')'], []).  % (())()
-    D = 2.
+?- paren(D, ['(','(',')',')','(',')'], []).  % (())()
+  D = 2.
 </pre>
 '''