English translation for del/3 added.

3 files changed, 94 insertions, 5 deletions

diff --git a/prolog/problems/lists/del_3/en.py b/prolog/problems/lists/del_3/en.py
index 99f87ca..d6e1e30 100644
--- a/prolog/problems/lists/del_3/en.py
+++ b/prolog/problems/lists/del_3/en.py
@@ -1,5 +1,5 @@
 name = 'del/3'
-slug = 'delete an element from list'
+slug = 'delete element from list'
 
 description = '''\
 <p><code>del(X, L1, L2)</code>: the list <code>L2</code> is obtained from <code>L1</code> by deleting element <code>X</code>.</p>
@@ -15,4 +15,93 @@ description = '''\
   X = 3, L = [1,2].
 </pre>'''
 
-hint = {}
+plan = ['''
+<p style="text-align: center;">
+    <img style="display: inline-block; width: 40%; border-right: 1px solid lightgray;" src="[%@resource plan_a.svg%]" />
+    <img style="display: inline-block; width: 40%;" src="[%@resource plan_b.svg%]" />
+</p>
+<p>This exercise is very similar to the exercise <code>memb/2</code>, except that this time we also delete
+the element we are looking for. Where in the list can element <code>X</code> be hiding?
+Remember that a list has two parts: head and tail. Therefore there are two possibilies!</p>
+''', '''\
+<p>What is the simplest option? Perhaps deleting the first element?</p>
+''', '''\
+<p>How do I delete from the list's tail? Just divide the list into its head and tail, recursively (as
+the problem is one element smaller now) delete from the tail, and at the end don't forget about the
+head previously taken away.</p>
+''', '''\
+<p>Recursive step: if we assume <code>NewTail</code> is the tail with element <code>X</code> already deleted,
+then <code>[H|NewTail]</code> is the whole list with element <code>X</code> deleted.</p>
+''']
+
+hint = {
+    'eq_instead_of_equ': '''\
+<p>The operator <code>==</code> is "stricter" than operator <code>=</code> in the sense that
+for the latter it is enough to be able to make the two operands equal (unification). Perhaps by using <code>=</code>
+you can make the predicate <code>del/3</code> more general (e.g. able to work with output arguments becoming inputs).</p>
+<p>Of course, you can also solve the exercise without explicit use of either of these two operators, just
+remember that unification is implicitly performed with the predicate's arguments (head of clause).</p>
+''',
+
+    'eq_instead_of_equ_markup': '''\
+<p>Perhaps the operator for unification (=) would be better?</p>
+''',
+
+    'base_case': '''\
+<p><img src="[%@resource base_case.svg%]" /></p>
+<p>Did you think of a base case? Where in the list is it the easiest to delete an element?</p>
+''',
+
+    'recursive_case': '''\
+<p>The base case is ok. However, what about the general recursive case?</p>
+''',
+
+    'predicate_always_false': '''\
+<p>It seems your predicate is <emph>always</emph> "false". Did you give it the correct name,
+or is it perhaps misspelled?</p>
+<p>If the name is correct, check whether something else is misspelled, perhaps there is a full stop instead of
+a comma or vice versa, or maybe you typed a variable name in lowercase?</p>
+<p>It is, of course, also possible that your conditions are too restrictive, or even impossible to satisfy
+(as would be, for example, the condition that an empty list <code>[]</code> is equal to a list with
+exactly three elements <code>[A,B,C]</code>,
+or something similarly impossible).</p>
+''',
+
+    'timeout': '''\
+<p>Is there an infinite recursion at work here? How will it ever stop?</p>
+<p>Or perhaps is there a missing, faulty, or simply incompatible (with the general recursive case) base case?</p>
+''',
+
+    'del_from_empty_list_success': '''\
+<p>You can't delete an element from an empty list!</p>
+<p>If I delete an element from an empty list, this doesn't result in an empty list or anything else, but it
+simply shouldn't succeed. You don't even have to include a rule for this as prolog by default acts like that.
+You know how prolog loves to say "no"! :)</p>
+<p>If that is your base case, rethink it! Where in the list is it the easiest to delete an element?</p>
+''',
+
+    'lost_heads': '''\
+<p><img src="[%@resource lost_heads.svg%]" /></p>
+<p>The element has been successfully deleted, but all the others before it got deleted too, right?
+Did you forget to put the head back at the front of the list after returning from recursion?</p>
+<p>Try asking the following query:</p>
+<p><code>?- del(d, [a,b,c,d,e,f,g], L).</code></p>
+''',
+
+    'leading_heads_all_x': '''\
+<p><img src="[%@resource leading_heads_all_x.svg%]" /></p>
+<p>Did you forget (copy/paste?) and used <code>[X|T]</code> instead of the more general <code>[H|T]</code>
+in the recursive case?</p>
+<p>Of the following two queries one works and the other doesn't.</p>
+<p><code>?- del(d, [d,d,d,d,e,f,g], L).</code></p>
+<p><code>?- del(d, [a,b,c,d,e,f,g], L).</code></p>
+''',
+
+    'final_hint': '''\
+<p>Interesting tidbit. Inserting and deleting an element into/from the list are opposite operations.
+Just by playing around with the arguments you can solve <code>del/3</code> using <code>insert/3</code>.</p>
+<p>Logically the following holds: deleting element <code>X</code> from list <code>BigList</code> resulting
+in list <code>SmallList</code> is the same as <em>inserting</em> element <code>X</code>
+into list <code>SmallList</code> to get list <code>BigList</code> as a result. ;)</p>
+''',
+}
diff --git a/prolog/problems/lists/del_3/sl.py b/prolog/problems/lists/del_3/sl.py
index feee5e4..17df017 100644
--- a/prolog/problems/lists/del_3/sl.py
+++ b/prolog/problems/lists/del_3/sl.py
@@ -97,7 +97,7 @@ Si pozabil dati glavo nazaj na začetek seznama, ko se vračaš iz rekurzije?</p
 <p>Zanimivost: operaciji vstavljanja in brisanja iz seznama sta si ravno nasprotni. Če se malce poigraš z
 argumenti, lahko <code>del/3</code> rešiš kar z <code>insert/3</code>.</p>
 <p>Logično velja naslednje: če zbrišem <code>X</code> iz seznama <code>BigList</code> in dobim kot rezultat
-seznam <code>SmallList</code> je isto kot če <emph>vstavim</emph> <code>X</code> v seznam <code>SmallList</code> in dobim
+seznam <code>SmallList</code> je isto kot če <em>vstavim</em> <code>X</code> v seznam <code>SmallList</code> in dobim
 kot rezultat seznam <code>BigList</code>. ;)</p>
 ''',
 }
diff --git a/prolog/problems/lists/insert_3/en.py b/prolog/problems/lists/insert_3/en.py
index 0de098b..d246932 100644
--- a/prolog/problems/lists/insert_3/en.py
+++ b/prolog/problems/lists/insert_3/en.py
@@ -23,7 +23,7 @@ the problem is one element smaller now) insert into the tail, and at the end don
 head previously taken away.</p>
 ''', '''\
 <p>Recursive step: if we assume <code>NewTail</code> is the tail with already inserted element <code>X</code>,
-then <code>[H|NewTail]</code> is the whole list with the element <code>X</code> inserted.</p>
+then <code>[H|NewTail]</code> is the whole list with element <code>X</code> inserted.</p>
 ''']
 
 hint = {
@@ -79,7 +79,7 @@ or something similarly impossible).</p>
 <p><img src="[%@resource lost_heads.svg%]" /></p>
 <p>The element has been successfully inserted, but all the others before it are lost, right?
 Did you forget to put the head back at the front of the list after returning from recursion?</p>
-<p>Try asking prolog the following query and check <em>all</em> the solutions:</p>
+<p>Try asking the following query and check <em>all</em> the solutions:</p>
 <p><code>?- insert(q, [a,b,c,d], L).</code></p>
 ''',