From 2a4a1d39bfcfb8b258be96c180dde09a12345295 Mon Sep 17 00:00:00 2001
From: Aleksander Sadikov <aleksander.sadikov@fri.uni-lj.si>
Date: Tue, 15 Dec 2015 10:45:30 +0100
Subject: Add Slovenian translations for Prolog.{clp_fd,dcg}

---
 prolog/problems/clp_fd/gcd_3/sl.py           | 14 ++++++++++++++
 prolog/problems/clp_fd/magic_1/sl.py         | 14 ++++++++++++++
 prolog/problems/clp_fd/puzzle_abc_3/sl.py    | 10 ++++++++++
 prolog/problems/clp_fd/puzzle_beth_1/sl.py   | 11 +++++++++++
 prolog/problems/clp_fd/puzzle_momson_2/sl.py | 10 ++++++++++
 prolog/problems/clp_fd/puzzle_ratio_2/sl.py  | 10 ++++++++++
 prolog/problems/clp_fd/tobase_3/sl.py        | 17 +++++++++++++++++
 7 files changed, 86 insertions(+)
 create mode 100644 prolog/problems/clp_fd/gcd_3/sl.py
 create mode 100644 prolog/problems/clp_fd/magic_1/sl.py
 create mode 100644 prolog/problems/clp_fd/puzzle_abc_3/sl.py
 create mode 100644 prolog/problems/clp_fd/puzzle_beth_1/sl.py
 create mode 100644 prolog/problems/clp_fd/puzzle_momson_2/sl.py
 create mode 100644 prolog/problems/clp_fd/puzzle_ratio_2/sl.py
 create mode 100644 prolog/problems/clp_fd/tobase_3/sl.py

(limited to 'prolog/problems/clp_fd')

diff --git a/prolog/problems/clp_fd/gcd_3/sl.py b/prolog/problems/clp_fd/gcd_3/sl.py
new file mode 100644
index 0000000..9ef1a87
--- /dev/null
+++ b/prolog/problems/clp_fd/gcd_3/sl.py
@@ -0,0 +1,14 @@
+# coding=utf-8
+
+name = 'gcd/3'
+slug = 'Največji skupni delitelj'
+
+description = '''\
+<p><code>gcd(X, Y, GCD)</code>: <code>GCD</code> je največji skupni delitelj števil <code>X</code> in <code>Y</code>. Implementiraj ta predikat z uporabo omejitev.</p>
+<p>Namig: poskusi najprej napisati predikat, ki poišče <em>vse</em> skupne delitelje dveh števil.</p>
+<pre>
+  ?- gcd(36, 84, GCD).
+    GCD = 12.
+</pre>'''
+
+hint = {}
diff --git a/prolog/problems/clp_fd/magic_1/sl.py b/prolog/problems/clp_fd/magic_1/sl.py
new file mode 100644
index 0000000..8cf040e
--- /dev/null
+++ b/prolog/problems/clp_fd/magic_1/sl.py
@@ -0,0 +1,14 @@
+# coding=utf-8
+
+name = 'magic/1'
+slug = '3x3 magični kvadrat'
+
+description = '''\
+<p><code>magic(S)</code>: seznam <code>S</code> predstavlja 3×3 magični kvadrat (<code>S</code> je permutacija števil 1 do 9 -- tri števila tvorijo eno vrstico). Vsote števil v vsaki vrstici, stolpcu in glavni diagonali magičnega kvadrata so enake. Implementiraj ta predikat z uporabo omejitev. Predikat naj vrne vse rešitve, eno po eno.</p>
+<pre>
+  ?- magic(S).
+    S = [2, 7, 6, 9, 5, 1, 4, 3, 8] ;
+    …
+</pre>'''
+
+hint = {}
diff --git a/prolog/problems/clp_fd/puzzle_abc_3/sl.py b/prolog/problems/clp_fd/puzzle_abc_3/sl.py
new file mode 100644
index 0000000..118481a
--- /dev/null
+++ b/prolog/problems/clp_fd/puzzle_abc_3/sl.py
@@ -0,0 +1,10 @@
+# coding=utf-8
+
+name = 'puzzle_abc/3'
+slug = 'Uganka z leti: ABC'
+
+description = '''\
+<p>Oseba <code>A</code> je dve leti starejša od osebe <code>B</code>, ki je dvakrat starejša od osebe <code>C</code>. Skupaj so osebe A, B in C stare 27 let.</p>
+<p>Napiši predikat <code>puzzle_abc(A, B, C)</code>, ki izračuna koliko so stare osebe A, B in C.</p>'''
+
+hint = {}
diff --git a/prolog/problems/clp_fd/puzzle_beth_1/sl.py b/prolog/problems/clp_fd/puzzle_beth_1/sl.py
new file mode 100644
index 0000000..261ec74
--- /dev/null
+++ b/prolog/problems/clp_fd/puzzle_beth_1/sl.py
@@ -0,0 +1,11 @@
+# coding=utf-8
+
+name = 'puzzle_beth/1'
+slug = 'Uganka z leti: Beti'
+
+description = '''\
+<p>Ko so Beti vprašali koliko je stara, je odgovorila takole "Čez dve leti bom dvakrat starejša kot sem bila pet let nazaj".</p>
+<p>Napiši predikat <code>puzzle_beth(X)</code>, ki izračuna njeno trenutno starost <code>X</code>.</p>
+'''
+
+hint = {}
diff --git a/prolog/problems/clp_fd/puzzle_momson_2/sl.py b/prolog/problems/clp_fd/puzzle_momson_2/sl.py
new file mode 100644
index 0000000..593f153
--- /dev/null
+++ b/prolog/problems/clp_fd/puzzle_momson_2/sl.py
@@ -0,0 +1,10 @@
+# coding=utf-8
+
+name = 'puzzle_momson/2'
+slug = 'Uganka z leti: mama in sin'
+
+description = '''\
+<p>Mama in sin sta skupaj stara 66 let. Mamina leta so ravno sinova obrnjena leta (obrnjene so cifre). Koliko sta stara?</p>
+<p>Napiši predikat <code>puzzle_momson(M, S)</code>, ki izračuna starost mame <code>M</code> in sina <code>S</code>.</p>'''
+
+hint = {}
diff --git a/prolog/problems/clp_fd/puzzle_ratio_2/sl.py b/prolog/problems/clp_fd/puzzle_ratio_2/sl.py
new file mode 100644
index 0000000..826e66f
--- /dev/null
+++ b/prolog/problems/clp_fd/puzzle_ratio_2/sl.py
@@ -0,0 +1,10 @@
+# coding=utf-8
+
+name = 'puzzle_ratio/2'
+slug = 'Uganka z leti: razmerje'
+
+description = '''\
+<p>Trenutni starosti osebe <code>A</code> in osebe <code>B</code> sta v razmerju 5:4. Čez tri leta bo razmerje njunih let postalo 11:9.</p>
+<p>Napiši predikat <code>puzzle_ratio(A, B)</code>, ki izračuna starost osebe <code>A</code> in osebe <code>B</code>.</p>'''
+
+hint = {}
diff --git a/prolog/problems/clp_fd/tobase_3/sl.py b/prolog/problems/clp_fd/tobase_3/sl.py
new file mode 100644
index 0000000..a775808
--- /dev/null
+++ b/prolog/problems/clp_fd/tobase_3/sl.py
@@ -0,0 +1,17 @@
+# coding=utf-8
+
+name = 'tobase/3'
+slug = 'Pretvori števila v/iz desetiškega sistema'
+
+description = '''\
+<p><code>tobase(Number, B, X)</code>: število <code>Number</code> je v desetiškem sistemu. <code>X</code> predstavlja to število v sistemu z bazo <code>B</code>. Implementiraj predikat z uporabo omejitev. Omeji vrednost <code>B</code> na interval [2..10].</p>
+<pre>
+  ?- tobase(42, 2, X).
+    X = 101010.
+  ?- tobase(N, 2, 101010).
+    N = 42.
+  ?- tobase(42, B, 101010).
+    B = 2.
+</pre>'''
+
+hint = {}
-- 
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