From 388b32039898cc8f1784378689007254eb7a33b6 Mon Sep 17 00:00:00 2001 From: Timotej Lazar Date: Wed, 13 Jan 2016 13:51:15 +0100 Subject: Remove space-padding from
 blocks

---
 prolog/problems/clp_fd/gcd_3/en.py    |  4 ++--
 prolog/problems/clp_fd/gcd_3/sl.py    |  4 ++--
 prolog/problems/clp_fd/magic_1/en.py  |  6 +++---
 prolog/problems/clp_fd/magic_1/sl.py  |  6 +++---
 prolog/problems/clp_fd/tobase_3/en.py | 12 ++++++------
 prolog/problems/clp_fd/tobase_3/sl.py | 12 ++++++------
 6 files changed, 22 insertions(+), 22 deletions(-)

(limited to 'prolog/problems/clp_fd')

diff --git a/prolog/problems/clp_fd/gcd_3/en.py b/prolog/problems/clp_fd/gcd_3/en.py
index 7953eb1..8891d54 100644
--- a/prolog/problems/clp_fd/gcd_3/en.py
+++ b/prolog/problems/clp_fd/gcd_3/en.py
@@ -7,8 +7,8 @@ description = '''\
 

gcd(X, Y, GCD): GCD is the greatest common divisor of X and Y. Implement this predicate using constraints.

Hint: try writing a predicate to find all common divisors of two numbers first.

-  ?- gcd(36, 84, GCD).
-    GCD = 12.
+?- gcd(36, 84, GCD).
+  GCD = 12.
 
''' hint = {} diff --git a/prolog/problems/clp_fd/gcd_3/sl.py b/prolog/problems/clp_fd/gcd_3/sl.py index 9ef1a87..f5016fa 100644 --- a/prolog/problems/clp_fd/gcd_3/sl.py +++ b/prolog/problems/clp_fd/gcd_3/sl.py @@ -7,8 +7,8 @@ description = '''\

gcd(X, Y, GCD): GCD je največji skupni delitelj števil X in Y. Implementiraj ta predikat z uporabo omejitev.

Namig: poskusi najprej napisati predikat, ki poišče vse skupne delitelje dveh števil.

-  ?- gcd(36, 84, GCD).
-    GCD = 12.
+?- gcd(36, 84, GCD).
+  GCD = 12.
 
''' hint = {} diff --git a/prolog/problems/clp_fd/magic_1/en.py b/prolog/problems/clp_fd/magic_1/en.py index c8b5a1a..0798164 100644 --- a/prolog/problems/clp_fd/magic_1/en.py +++ b/prolog/problems/clp_fd/magic_1/en.py @@ -6,9 +6,9 @@ slug = 'generate a 3x3 magic square' description = '''\

magic(S): the list S represents a 3×3 magic square (S is a permutation of numbers 1 to 9 - three numbers for each row). The sums of numbers in each row, column and diagonal of a magic squre are equal. Implement this predicate using constraints. Your code should return all possible solutions.

-  ?- magic(S).
-    S = [2, 7, 6, 9, 5, 1, 4, 3, 8] ;
-    …
+?- magic(S).
+  S = [2, 7, 6, 9, 5, 1, 4, 3, 8] ;
+  …
 
''' hint = {} diff --git a/prolog/problems/clp_fd/magic_1/sl.py b/prolog/problems/clp_fd/magic_1/sl.py index 8cf040e..fa73a01 100644 --- a/prolog/problems/clp_fd/magic_1/sl.py +++ b/prolog/problems/clp_fd/magic_1/sl.py @@ -6,9 +6,9 @@ slug = '3x3 magični kvadrat' description = '''\

magic(S): seznam S predstavlja 3×3 magični kvadrat (S je permutacija števil 1 do 9 -- tri števila tvorijo eno vrstico). Vsote števil v vsaki vrstici, stolpcu in glavni diagonali magičnega kvadrata so enake. Implementiraj ta predikat z uporabo omejitev. Predikat naj vrne vse rešitve, eno po eno.

-  ?- magic(S).
-    S = [2, 7, 6, 9, 5, 1, 4, 3, 8] ;
-    …
+?- magic(S).
+  S = [2, 7, 6, 9, 5, 1, 4, 3, 8] ;
+  …
 
''' hint = {} diff --git a/prolog/problems/clp_fd/tobase_3/en.py b/prolog/problems/clp_fd/tobase_3/en.py index c05ab2a..41f8889 100644 --- a/prolog/problems/clp_fd/tobase_3/en.py +++ b/prolog/problems/clp_fd/tobase_3/en.py @@ -6,12 +6,12 @@ slug = 'convert numbers from/to the decimal system' description = '''\

tobase(Number, B, X): given a Number in the decimal system (base 10), X represents the same number in the system with base B. Implement this predicate using constraints. Limit the value of B to the interval [2..10].

-  ?- tobase(42, 2, X).
-    X = 101010.
-  ?- tobase(N, 2, 101010).
-    N = 42.
-  ?- tobase(42, B, 101010).
-    B = 2.
+?- tobase(42, 2, X).
+  X = 101010.
+?- tobase(N, 2, 101010).
+  N = 42.
+?- tobase(42, B, 101010).
+  B = 2.
 
''' hint = {} diff --git a/prolog/problems/clp_fd/tobase_3/sl.py b/prolog/problems/clp_fd/tobase_3/sl.py index a775808..72879af 100644 --- a/prolog/problems/clp_fd/tobase_3/sl.py +++ b/prolog/problems/clp_fd/tobase_3/sl.py @@ -6,12 +6,12 @@ slug = 'Pretvori števila v/iz desetiškega sistema' description = '''\

tobase(Number, B, X): število Number je v desetiškem sistemu. X predstavlja to število v sistemu z bazo B. Implementiraj predikat z uporabo omejitev. Omeji vrednost B na interval [2..10].

-  ?- tobase(42, 2, X).
-    X = 101010.
-  ?- tobase(N, 2, 101010).
-    N = 42.
-  ?- tobase(42, B, 101010).
-    B = 2.
+?- tobase(42, 2, X).
+  X = 101010.
+?- tobase(N, 2, 101010).
+  N = 42.
+?- tobase(42, B, 101010).
+  B = 2.
 
''' hint = {} -- cgit v1.2.1