From 0331b2ff089f33a33f66470cec305ff08f829a30 Mon Sep 17 00:00:00 2001 From: Aleksander Sadikov Date: Tue, 30 Aug 2016 02:33:37 +0200 Subject: English translation for last_elem/2 added. --- prolog/problems/lists/last_elem_2/en.py | 84 ++++++++++++++++++++++++++++++++- prolog/problems/lists/last_elem_2/sl.py | 2 +- 2 files changed, 84 insertions(+), 2 deletions(-) (limited to 'prolog/problems/lists/last_elem_2') diff --git a/prolog/problems/lists/last_elem_2/en.py b/prolog/problems/lists/last_elem_2/en.py index 93c7c05..5eec3b8 100644 --- a/prolog/problems/lists/last_elem_2/en.py +++ b/prolog/problems/lists/last_elem_2/en.py @@ -10,4 +10,86 @@ description = '''\ X = 1. ''' -hint = {} +plan = ['''\ +

It's easy to access the first element in a list, but to get to the last element one needs to +recursively go through the whole list.

+''', '''\ +

The list can be divided into its head and tail, and the search can proceed with the tail. +The problem is now smaller (the tail is shorter than the whole list), so we can use recursion.

+''', '''\ +

If X is the last element of tail T, then X is also +the last element of the whole list that looks like [H|T].

+'''] + +hint = { + 'eq_instead_of_equ': '''\ +

The operator == is "stricter" than operator = in the sense that +for the latter it is enough to be able to make the two operands equal (unification). Perhaps by using = +you can make the predicate last_elem/2 more general (e.g. able to work with output arguments becoming inputs).

+

Of course, you can also solve the exercise without explicit use of either of these two operators, just +remember that unification is implicitly performed with the predicate's arguments (head of clause).

+''', + + 'eq_instead_of_equ_markup': '''\ +

Perhaps the operator for unification (=) would be better?

+''', + + 'base_case': '''\ +

Did you think of a base case? What's the simplest possible case? What if the list contains only one element?

+''', + + '[]_should_not_succeed': '''\ +

How did you succeed to find a last element in an empty list? You likely need a different base case.

+''', + + 'list_returned': '''\ +

You are returning a list instead of an element.

+''', + + 'clumsy_conc_use': '''\ +

Are you using conc/3? An interesting idea. Don't forget that the second list you're +concatenating must be of length one if you want to achieve the desired effect. +So a pattern of the form [X], right?

+''', + + 'unsuccessful_conc_use': '''\ +

Are you using conc/3? An interesting idea; it is possible to solve in this way. +However, a bit of tweaking is still needed. Don't forget that conc/3 has three arguments, +and all three are lists. Think about what kind of a pattern do you need...

+''', + + 'recursive_case': '''\ +

The base case is ok. However, what about the general recursive case?

+''', + + 'predicate_always_false': '''\ +

It seems your predicate is always "false". Did you give it the correct name, +or is it perhaps misspelled?

+

If the name is correct, check whether something else is misspelled, perhaps there is a full stop instead of +a comma or vice versa, or maybe you typed a variable name in lowercase?

+

It is, of course, also possible that your conditions are too restrictive, or even impossible to satisfy +(as would be, for example, the condition that an empty list [] is equal to a list with +exactly three elements [A,B,C], +or something similarly impossible).

+''', + + 'timeout': '''\ +

Is there an infinite recursion at work here? How will it ever stop?

+

Or perhaps is there a missing, faulty, or simply incompatible (with the general recursive case) base case?

+''', + + 'final_hint': '''\ +

Interesting fact: predicate conc/3 can be used to search for patterns in lists. The last +element in a list is also a kind of pattern. What happens if we concatenate an arbitrary list _ +and a list of length one (in this order)? A list of length one is of course written as +[Element].

+

Try asking the following query:

+

?- conc(_, [Element], [a,b,c,d,e,f,q]).

+

So, can you now fetch the list's last element using conc/3? This will be very useful in +further exercises. On the other hand, of course, accessing the last element of a list is still quite +expensive, it's done in O(n) time. Therefore, if it's not important which element of a list is to be used, +or where in a list a new element is to be added, always work with the head.

+

And what does this query do? ;)

+

?- conc([a,b,c], [q], L).

+''', +} diff --git a/prolog/problems/lists/last_elem_2/sl.py b/prolog/problems/lists/last_elem_2/sl.py index afba57a..961963c 100644 --- a/prolog/problems/lists/last_elem_2/sl.py +++ b/prolog/problems/lists/last_elem_2/sl.py @@ -47,7 +47,7 @@ implicitno že kar v argumentih predikata (glavi stavka).

'clumsy_conc_use': '''\

Uporabljaš conc/3? Zanimiva ideja. Ne pozabi, da mora drugi seznam, ki ga konkateniraš -biti dolžine ena, če hočeš doseči to kar želiš. Torej vzorec oblike [X], kajne?

+biti dolžine ena, če hočeš doseči to kar želiš. Torej vzorec oblike [X], kajne?

''', 'unsuccessful_conc_use': '''\ -- cgit v1.2.1