From 388b32039898cc8f1784378689007254eb7a33b6 Mon Sep 17 00:00:00 2001 From: Timotej Lazar Date: Wed, 13 Jan 2016 13:51:15 +0100 Subject: Remove space-padding from
 blocks

---
 prolog/problems/old_exams/pascal_3/en.py | 24 ++++++++++++------------
 1 file changed, 12 insertions(+), 12 deletions(-)

(limited to 'prolog/problems/old_exams/pascal_3')

diff --git a/prolog/problems/old_exams/pascal_3/en.py b/prolog/problems/old_exams/pascal_3/en.py
index bd17577..8481bd6 100644
--- a/prolog/problems/old_exams/pascal_3/en.py
+++ b/prolog/problems/old_exams/pascal_3/en.py
@@ -1,27 +1,27 @@
 # coding=utf-8
 
 name = 'pascal/3'
-slug = 'pascal's triangle'
+slug = 'pascal’s triangle'
 
 description = '''\
 

The first five rows of the Pascal's triangle look like this:

-        1
-       1 1
-      1 2 1
-     1 3 3 1
-    1 4 6 4 1
+    1
+   1 1
+  1 2 1
+ 1 3 3 1
+1 4 6 4 1
 

Each row begins and ends with 1. Every other element can be obtained as a sum of the two values above it. Write the predicate pascal(I,J,N) that returns the J-th value in the I-th column of the Pascal's triangle. Your solution should return exactly one answer for any input (the I and J arguments start counting with 0; you can assume that 0 ≤ JI).

-  ?- pascal(0, 0, N).
-    N = 1.
-  ?- pascal(2, 1, N).
-    N = 2.
-  ?- pascal(4, 3, N).
-    N = 4.
+?- pascal(0, 0, N).
+  N = 1.
+?- pascal(2, 1, N).
+  N = 2.
+?- pascal(4, 3, N).
+  N = 4.
 
''' hint = {} -- cgit v1.2.1