From e63627ad942a7d2c9eebb86f15c96191e7408eb8 Mon Sep 17 00:00:00 2001 From: Martin Date: Mon, 5 Oct 2015 11:57:31 +0200 Subject: Added problem "counting". Some other small text corrections. --- python/problems/lists_and_for/contains_42/sl.py | 18 ++-- .../problems/lists_and_for/contains_string/sl.py | 9 +- python/problems/lists_and_for/counting/common.py | 109 +++++++++++++++++++++ python/problems/lists_and_for/counting/en.py | 16 +++ python/problems/lists_and_for/counting/sl.py | 90 +++++++++++++++++ .../while_and_if/consumers_anonymous/common.py | 20 ++-- .../while_and_if/consumers_anonymous/sl.py | 10 +- 7 files changed, 253 insertions(+), 19 deletions(-) create mode 100644 python/problems/lists_and_for/counting/common.py create mode 100644 python/problems/lists_and_for/counting/en.py create mode 100644 python/problems/lists_and_for/counting/sl.py (limited to 'python/problems') diff --git a/python/problems/lists_and_for/contains_42/sl.py b/python/problems/lists_and_for/contains_42/sl.py index 9477e29..fe6b57e 100644 --- a/python/problems/lists_and_for/contains_42/sl.py +++ b/python/problems/lists_and_for/contains_42/sl.py @@ -19,10 +19,12 @@ Seveda mora program delati za poljubne sezname in ne samo za seznam iz primera.< ''' for_loop = ['''\ -

Čez elemente v seznamu se najlažje sprehodimo s for zanko. +

Pregledati bo treba vse elemente v seznamu xs''', + '''\ +

Najlažje bo s for zanko. ''', '''\ -

Poskusi, kaj naredita naslednji dve vrstici:

+

Poskusii naslednji dve vrstici:

 for x in xs:
     print (x)
@@ -30,21 +32,25 @@ for x in xs:
              '''\
 

V zgornjem primeru z zanko for Pythonu naročimo naj se sprehodi čez seznam xs in na vsakem koraku trenutni element seznama shrani v spremenljivko x. -Kaj naj Python naredi s to spremenljivko, mu naročimo v zamaknjenih vrsticah. +Kaj naj Python naredi s to spremenljivko, je zapisano v zamaknjenih vrsticah. Tokrat vrednost le izpišemo.

'''] if_clause = ['''\ -

Poglej, ali je število 42? Uporabite pogojni stavek if!

''', +

Preveri, ali imamo število 42?

''', + '''\ +

Uporabi pogojni stavek if!

''', '''\
 if x == 42:
 
'''] seen_42 = ['''\ -

Kako si lahko zapomnimo, da smo videli 42? Uporabi novo spremenljivko!

+

Zapomni si, da si našel 42!

''', + '''\ +

Uporabi novo spremenljivko!

''', '''\ -

Spremenljivko na začetku nastavimo na False, npr.:

+

Spremenljivko na začetku nastavimo na False:

 videl42 = False
 
diff --git a/python/problems/lists_and_for/contains_string/sl.py b/python/problems/lists_and_for/contains_string/sl.py index 2f24458..d177463 100644 --- a/python/problems/lists_and_for/contains_string/sl.py +++ b/python/problems/lists_and_for/contains_string/sl.py @@ -18,10 +18,12 @@ xs = ['foo', 'bar', 'baz', 'Waldo', 'foobar'] ''' for_loop = ['''\ -

Čez elemente v seznamu se najlažje sprehodimo s for zanko. +

Pregledati bo treba vse elemente v seznamu xs''', + '''\ +

Najlažje bo s for zanko. ''', '''\ -

Poskusi, kaj naredita naslednji dve vrstici:

+

Poskusii naslednji dve vrstici:

 for x in xs:
     print (x)
@@ -29,7 +31,7 @@ for x in xs:
              '''\
 

V zgornjem primeru z zanko for Pythonu naročimo naj se sprehodi čez seznam xs in na vsakem koraku trenutni element seznama shrani v spremenljivko x. -Kaj naj Python naredi s to spremenljivko, mu naročimo v zamaknjenih vrsticah. +Kaj naj Python naredi s to spremenljivko, je zapisano v zamaknjenih vrsticah. Tokrat vrednost le izpišemo.

'''] if_clause = ['''\ @@ -39,6 +41,7 @@ if_clause = ['''\ if x == 'Waldo':
'''] + plan = ['''\

Plan je enak kot pri prvi nalogi:

diff --git a/python/problems/lists_and_for/counting/common.py b/python/problems/lists_and_for/counting/common.py
new file mode 100644
index 0000000..2d59182
--- /dev/null
+++ b/python/problems/lists_and_for/counting/common.py
@@ -0,0 +1,109 @@
+# coding=utf-8
+
+import re
+from python.util import has_token_sequence, string_almost_equal, \
+    string_contains_number, get_tokens, get_numbers, get_exception_desc
+from server.hints import Hint
+
+id = 203
+group = 'lists_and_for'
+number = 3
+visible = True
+
+solution = '''\
+xs = [42, 5, 4, -7, 2, 12, -3, -4, 11, 42, 2]
+
+stevec = 0
+for x in xs:
+    if x == 42:
+        stevec += 1
+print("Število 42 se v seznamu pojavi", stevec, "krat.")
+'''
+
+hint_type = {
+    'no_xs': Hint('no_xs'),
+    'for_loop': Hint('for_loop'),
+    'if_clause': Hint('if_clause'),
+    'printing': Hint('printing'),
+    'print_out_for': Hint('print_out_for'),
+    'final_hint': Hint('final_hint')
+}
+
+def test(python, code):
+    test_xs = [[42, 5, 4, -7, 2, 42, -3, -4, 11, 42, 2],
+               [42, 5, 4, -7, 2, 12, 42, -4, 11, 2],
+               [5, 4, -7, 2, 12, -3, -4, 11, 2],
+               [],
+               [42],
+               [42, 42],
+               [1, 2, 3, -42],
+               [1, 2, 3, 42, -42]]
+    test_out = [
+        3,
+        2,
+        0,
+        0,
+        1,
+        2,
+        0,
+        1
+    ]
+
+    n_correct = 0
+    tin = None
+    for xs_i, xs in enumerate(test_xs):
+        # change code to contain new xs instead of the one
+        # given by user
+        tcode = re.sub(r'^xs\s*=\s*\[.*?\]',
+                       'xs = ' + str(xs),
+                       code,
+                       flags = re.DOTALL | re.MULTILINE)
+
+        # use python session to call tcode
+        answers = python(code=tcode, inputs=[(None, None)], timeout=1.0)
+        output = answers[0][1]
+
+        if str(test_out[xs_i]) in output:
+            n_correct += 1
+        else:
+            tin = test_xs[xs_i]
+            tout = test_out[xs_i]
+
+    passed = n_correct == len(test_xs)
+    hints = [{'id': 'test_results', 'args': {'passed': n_correct, 'total': len(test_xs)}}]
+    if tin:
+        hints.append({'id': 'problematic_test_case', 'args': {'testin': str(tin), 'testout': str(tout)}})
+    if passed:
+        hints.append({'id': 'final_hint'})
+    return passed, hints
+
+def hint(python, code):
+    # run one test first to see if there are any exceptions
+    answer = python(code=code, inputs=[(None, None)], timeout=1.0)
+    exc = get_exception_desc(answer[0][3])
+    if exc: return exc
+
+    tokens = get_tokens(code)
+
+    # if has no xs, tell him to ask for values
+    if not has_token_sequence(tokens, ['xs', '=', '[']):
+        return [{'id' : 'no_xs'}]
+
+    # student does not have while or for: instruct him on loops
+    if not has_token_sequence(tokens, ['while']) and \
+       not has_token_sequence(tokens, ['for']):
+        return [{'id' : 'for_loop'}]
+
+    if not has_token_sequence(tokens, ['if']):
+        return [{'id' : 'if_clause'}]
+
+    # student is not using print function
+    if not has_token_sequence(tokens, ['print']):
+        return [{'id' : 'printing'}]
+
+    # student is not using print at the beginning of line
+    if not has_token_sequence(tokens, ['\n', 'print']):
+        return [{'id' : 'print_out_for'}]
+
+
+    return None
diff --git a/python/problems/lists_and_for/counting/en.py b/python/problems/lists_and_for/counting/en.py
new file mode 100644
index 0000000..805b37c
--- /dev/null
+++ b/python/problems/lists_and_for/counting/en.py
@@ -0,0 +1,16 @@
+# coding=utf-8
+
+id = 193
+name = 'Contains 42'
+slug = 'Contains 42'
+
+description = '''\
+

(translation missing)

''' + +hint = { + 'plan': '''\ +

(translation missing)

''', + + 'no_input_call': '''\ +

(translation missing)

''', +} diff --git a/python/problems/lists_and_for/counting/sl.py b/python/problems/lists_and_for/counting/sl.py new file mode 100644 index 0000000..67dc323 --- /dev/null +++ b/python/problems/lists_and_for/counting/sl.py @@ -0,0 +1,90 @@ +# coding=utf-8 +import server +mod = server.problems.load_language('python', 'sl') + + +id = 203 +name = 'Štej' +slug = 'Štej' + + +description = '''\ +

Napiši program, ki v podanem seznamu prešteje število ponovitev števila 42. +Seznam xs definiraj na vrhu programa, kot v prejšnjih nalogah, +izpis pa naj bo takšen: "Število 42 se v seznamu pojavi 2 krat."''' + +for_loop = ['''\ +

Pregledati bo treba vse elemente v seznamu xs''', + '''\ +

Najlažje s for zanko. +''', + '''\ +

Poskusi naslednji dve vrstici:

+
+for x in xs:
+    print (x)
+
''', + '''\ +

V zgornjem primeru z zanko for Pythonu naročimo naj se sprehodi čez seznam xs +in na vsakem koraku trenutni element seznama shrani v spremenljivko x. +Kaj naj Python naredi s to spremenljivko, je zapisano v zamaknjenih vrsticah. +V danem primeru vrednost le izpišemo.

'''] + +if_clause = ['''\ +

Preveri, ali imamo število 42?

''', + '''\ +

Uporabi pogojni stavek if!

''', + '''\ +
+if x == 42:
+
'''] + +count_42 = ['''\ +

Zapomni si, da si našel 42! Povečaj števec!

''', + '''\ +

Števec na začetku nastavimo na 0

+
+stevec = 0
+
+

in ga tekom zanke ustrezno spreminjamo.'''] + +plan = ['''\ +

Plan: Preglej vse elemente v seznamu in vsakič, ko srečaš 42, povečaj +števec za 1.

+''', + '''\ +

Bolj podroben plan:

+
+Za vsak element v seznamu
+    Poglej, ali je 42?
+        Če je, povečaj števec.
+Izpiši števec.
+
+

Zdaj pa je potrebno le še slovenščino prevesti v Python.

+''', + for_loop, + if_clause, + count_42] + +hint = { + 'no_xs': ['''\ +

Program mora imeti na začetku definiran seznam xs.

'''], + + 'for_loop': for_loop, + + 'if_clause': if_clause, + + 'printing': ['''\ +

Izpiši rezultat.

'''], + + 'print_out_for': ['''\ +

Pazi, da izpišeš rezultat izven zanke!

'''], + + 'final_hint:': ['''\ +

Nalogo lahko rešiš bistveno hitreje, če poznaš metodo count

+
+ xs = [42, 5, 4, -7, 2, 12, -3, -4, 11, 42, 2]
+ print('Število 42 se v seznamu pojavi', xs.count(42), 'krat.')
+
'''] + +} diff --git a/python/problems/while_and_if/consumers_anonymous/common.py b/python/problems/while_and_if/consumers_anonymous/common.py index ff3f928..07a0ebf 100644 --- a/python/problems/while_and_if/consumers_anonymous/common.py +++ b/python/problems/while_and_if/consumers_anonymous/common.py @@ -32,6 +32,7 @@ hint_type = { 'final_hint': Hint('final_hint'), 'summation': Hint('summation'), 'counting': Hint('counting'), + 'counting_with_0': Hint('counting_with_0'), 'problematic_test_case': Hint('problematic_test_case'), } @@ -53,7 +54,8 @@ def test(python, code): (105, 3), (10, 10), (10, 10), - (9, 9) + (9, 9), + (0, 0) ] # List of outputs: (expression result, stdout, stderr, exception). @@ -114,14 +116,18 @@ def hint(python, code): # student's answer is not correct (three possibilities) if not string_almost_equal(answer[0][1], 15) or \ - not string_almost_equal(answer[0][2], 105) or \ - not string_almost_equal(answer[0][3], 20): + not string_almost_equal(answer[1][1], 105) or \ + not string_almost_equal(answer[2][1], 20): return [{'id' : 'summation'}] - # student's answer is not correct (three possibilities) - if not string_almost_equal(answer[0][1], 2) or \ - not string_almost_equal(answer[0][2], 3) or \ - not string_almost_equal(answer[0][3], 10): + # student's counting of items, when last price iz zero is incorrect + if not string_almost_equal(answer[0][1], 2) and \ + string_almost_equal(answer[0][1], 3): + return [{'id' : 'counting_with_0'}] + + # counting in general is incorrect + if not string_almost_equal(answer[1][1], 3) or \ + not string_almost_equal(answer[2][1], 10): return [{'id' : 'counting'}] return None diff --git a/python/problems/while_and_if/consumers_anonymous/sl.py b/python/problems/while_and_if/consumers_anonymous/sl.py index ee2700c..284abbc 100644 --- a/python/problems/while_and_if/consumers_anonymous/sl.py +++ b/python/problems/while_and_if/consumers_anonymous/sl.py @@ -96,6 +96,9 @@ hint = { 'counting': ['''

Napaka pri štetju stvari.

'''], + 'counting_with_0': ['''

Napaka pri štetju, kadar je zadnja cena 0.

''', + '''

Števec povečaj, le če je cena > 0

'''], + 'name_error' : [mod.general_msg['error_head'], mod.general_msg['general_exception'], mod.general_msg['name_error'], @@ -107,9 +110,10 @@ hint = { Pravilna vsota [%=sum%], pravilno število stvari: [%=count%]'''], 'final_hint': ['''\ -

Odlično!Naloga rešena.

-Še zanimivost: v while zanki smo negirali ustavitveni pogoj tako, da smo negirali posamezne pogoje in -spremenili pogoj or v and. Temu pravimo De Morganov zakon. +

Odlično! Naloga rešena.

+Še zanimivost: v while zanki smo dobili ustavitveni pogoj tako, da smo negirali pogoj iz teksta (ali vnesemo 0 ali je +vnešenih deset števil ali ko vsota cen doseže ali preseže 100 evrov). Pri tem smo ali (or) spremenili v in (and): +cena > 0 and stevec < 10 and vsota < 100. Temu pravimo De Morganov zakon. '''], 'eof_error':[mod.general_msg['eof_error'], -- cgit v1.2.1