from operator import itemgetter import prolog.engine import prolog.util import socket from server.hints import Hint, HintPopup import server.problems id = 115 number = 7 visible = True facts = None solution = '''\ divide([], [], []). divide([X], [X], []). divide([H1,H2|T], [H1|L1], [H2|L2]) :- divide(T, L1, L2). ''' hint_type = { 'eq_instead_of_equ_markup': HintPopup('eq_instead_of_equ_markup'), 'eq_instead_of_equ': Hint('eq_instead_of_equ'), 'predicate_always_false': Hint('predicate_always_false'), 'base_case': Hint('base_case'), 'recursive_case': Hint('recursive_case'), 'timeout': Hint('timeout'), 'base_case_arbitrary': Hint('base_case_arbitrary'), 'second_base_case_missing': Hint('second_base_case_missing'), 'unsuccessful_conc_use': Hint('unsuccessful_conc_use'), 'forcing_result_onto_recursion': Hint('forcing_result_onto_recursion'), } test_cases = [ ('divide([], A, B)', [{'A': '[]', 'B': '[]'}]), ('divide([q], A, B)', [{'A': '[q]', 'B': '[]'}]), ('divide([h, e, t, y, q, w], A, B)', [{'A': '[h, t, q]', 'B': '[e, y, w]'}]), ('divide([j, e, y, u, i], A, B)', [{'A': '[j, y, i]', 'B': '[e, u]'}]), ('divide(A, [t, q, y], [l, e, r])', [{'A': '[t, l, q, e, y, r]'}]), ] def test(code, aux_code): n_correct = 0 engine_id = None try: engine_id, output = prolog.engine.create(code=code+aux_code, timeout=1.0) if engine_id is not None and 'error' not in map(itemgetter(0), output): # Engine successfully created, and no syntax error in program. for query, answers in test_cases: if prolog.engine.check_answers(engine_id, query=query, answers=answers, timeout=1.0): n_correct += 1 except socket.timeout: pass finally: if engine_id: prolog.engine.destroy(engine_id) hints = [{'id': 'test_results', 'args': {'passed': n_correct, 'total': len(test_cases)}}] return n_correct, len(test_cases), hints def hint(code, aux_code): tokens = prolog.util.tokenize(code) try: engine_id, output = prolog.engine.create(code=code+aux_code, timeout=1.0) # strict equality testing instead of simple matching # this is usually (but not necessarily) wrong targets = [prolog.util.Token('EQ', '==')] marks = [(t.pos, t.pos + len(t.val)) for t in tokens if t in targets] if marks: return [{'id': 'eq_instead_of_equ_markup', 'start': m[0], 'end': m[1]} for m in marks] + \ [{'id': 'eq_instead_of_equ'}] # general unsuccessful use of conc (not appropriate for this exercise) if prolog.util.Token('NAME', 'conc') in tokens: return [{'id': 'unsuccessful_conc_use'}] # recursion is getting bigger and bigger # forcing result onto recursion; case of divide(T, [H1|L1], [H2|L2]) if not prolog.engine.ask_truthTO(engine_id, 'divide([a,b,c], _, _)') and \ prolog.engine.ask_truthTO(engine_id, 'asserta( divide([cob], [yowza,cob], [brix]) ), divide([yowza,brix,cob], [cob], []), retract( divide([cob], [yowza,cob], [brix]) )'): return [{'id': 'forcing_result_onto_recursion'}] # base case succeeds with arbitrary result if prolog.engine.ask_truthTO(engine_id, 'divide([], L1, L2), (var(L1) ; var(L2))') or \ prolog.engine.ask_truthTO(engine_id, 'divide([q], L1, L2), (var(L1) ; var(L2))') or \ prolog.engine.ask_truthTO(engine_id, 'divide([q], [q|L1], L2), (var(L1) ; var(L2))'): return [{'id': 'base_case_arbitrary'}] # one base case ok, the other one is missing (or bad) # only trigger when recursion also works, because that makes more sense to the student # than immediately telling him or her that there is another base case missing if prolog.engine.ask_truthTO(engine_id, 'divide([a,b], [a], [b]), \+ divide([a,b,c], [a,c], [b]) ; \+ divide([a,b], [a], [b]), divide([a,b,c], [a,c], [b])'): return [{'id': 'second_base_case_missing'}] # missing/failed base case if not prolog.engine.ask_truth(engine_id, 'divide([], [], [])'): return [{'id': 'base_case'}] # # target predicate seems to always be false # if not prolog.engine.ask_truthTO(engine_id, 'divide([_,_,_,_,_], _, _)') and \ # not prolog.engine.ask_truthTO(engine_id, 'divide([_,_,_,_,_,_], _, _)'): # return [{'id': 'predicate_always_false'}] # base cases work, the recursive doesn't (but it doesn't timeout) # this may be left as the last, most generic hint if not prolog.engine.ask_truth(engine_id, 'divide([qa,qb,qc,qd], [qa,qc], [qb,qd])'): return [{'id': 'recursive_case'}] except socket.timeout as ex: return [{'id': 'timeout'}] finally: if engine_id: prolog.engine.destroy(engine_id) return []