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|
# coding=utf-8
from operator import itemgetter
import socket
import prolog.engine
import prolog.util
from server.hints import Hint, HintSequence
import server.problems
id = 98
group = 'family_relations'
number = 5
visible = True
facts = 'family_relations'
solution = '''\
sister98(X, Y) :-
parent(P, X),
parent(P, Y),
female(X),
X \== Y.
aunt(X, Y) :-
sister98(X, Z),
parent(Z, Y).
'''
hint_type = {
'x_and_y_mixed_up': Hint('x_and_y_mixed_up'),
'precedence_fail': Hint('precedence_fail'),
'x_must_be_female': Hint('x_must_be_female'),
'aunt_vs_mother': Hint('aunt_vs_mother'),
'x_need_not_be_parent': Hint('x_need_not_be_parent'),
'y_need_not_be_parent': Hint('y_need_not_be_parent'),
}
test_cases = [
# TODO
]
def test(program, solved_problems):
code = (program + '\n' +
server.problems.solutions_for_problems('prolog', solved_problems) + '\n' +
server.problems.load_facts('prolog', facts).facts)
engine_id = None
try:
engine_id, output = prolog.engine.create(code=code, timeout=1.0)
if not engine_id or 'error' in map(itemgetter(0), output):
# Engine creation failed, or syntax error in code.
return 0, len(test_cases)
n_correct = 0
for query, answers in test_cases:
# Limit inferences for each solution to curb unbounded recursion.
limited = 'call_with_inference_limit(({}), 100000, _)'.format(query)
if prolog.engine.check_answers(engine_id, query=limited, answers=answers, timeout=1.0):
n_correct += 1
finally:
if engine_id:
prolog.engine.destroy(engine_id)
passed = n_correct == len(test_cases)
hints = [{'id': 'test_results', 'args': {'passed': n_correct, 'total': len(test_cases)}}]
return passed, hints
def hint(program, solved_problems):
tokens = prolog.util.tokenize(program)
code = (program + '\n' +
server.problems.solutions_for_problems('prolog', solved_problems) + '\n' +
server.problems.load_facts('prolog', facts).facts)
engine_id = None
try:
engine_id, output = prolog.engine.create(code=code, timeout=1.0)
if not engine_id:
raise Exception('Prolog engine failed to create.')
# X and Y mixed up
# warning: knowledge base dependent
# independent: match on findall(X/Y, (sister(Y, P), parent(P, X)), L)
if prolog.engine.ask_truth(engine_id,
'findall(X/Y, aunt(X, Y), \
[vanessa/sally, patricia/sally, joanne/melanie, john/vanessa, susan/patricia])'):
return [{'id', 'x_and_y_mixed_up'}]
# precedence fail (AND block vs OR block)
# case in point: female(X), parent(P, Y), brother(P, X) ; sister(P, X)
# warning: knowledge base dependent
if prolog.util.Token('SEMI', ';') in tokens and prolog.engine.ask_truth(engine_id,
'findall(_, aunt(X, Y), L), length(L, 15)'):
return [{'id', 'precedence_fail'}]
# X must be female
if prolog.engine.ask_truth(engine_id,
'aunt(X, _), male(X)'):
return [{'id', 'x_must_be_female'}]
# X and P can be the same person
# this can occur if the problem is not solved using sister/2
if prolog.engine.ask_truth(engine_id,
'aunt(X, Y), mother(X, Y)'):
return [{'id', 'aunt_vs_mother'}]
# X does not necessarily need to be a parent
# perhaps risky as only one aunt that is not a parent exists in DB (melanie)
if prolog.engine.ask_one(engine_id,
'aunt(X, _), \+ parent(X, _)') == 'false':
return [{'id': 'x_need_not_be_parent'}]
# Y does not necessarily need to be a parent
# perhaps risky as only one such nephew exists in DB (susan)
if prolog.engine.ask_one(engine_id,
'aunt(_, Y), \+ parent(Y, _)') == 'false':
return [{'id': 'y_need_not_be_parent'}]
except socket.timeout as ex:
pass
finally:
if engine_id:
prolog.engine.destroy(engine_id)
return None
|
