diff options
author | Martin Možina <martin.mozina@fri.uni-lj.si> | 2016-08-24 15:33:42 +0200 |
---|---|---|
committer | Martin Možina <martin.mozina@fri.uni-lj.si> | 2016-08-24 15:33:42 +0200 |
commit | acd5a646f0848bfb4616144119cb7e10d7b41f8f (patch) | |
tree | 8005fffeeef3b30b57a21d51ae46ec05f37bc5df /prolog/problems/family_relations/sister_2 | |
parent | 12378810ee9207536bfa0c264c1bf2a2b0296171 (diff) | |
parent | 9360424c9992b92efb4ab0c526eeebd722d54a6f (diff) |
Merge branch 'master' of 192.168.15.97:codeq-problems
Diffstat (limited to 'prolog/problems/family_relations/sister_2')
-rw-r--r-- | prolog/problems/family_relations/sister_2/en.py | 75 |
1 files changed, 69 insertions, 6 deletions
diff --git a/prolog/problems/family_relations/sister_2/en.py b/prolog/problems/family_relations/sister_2/en.py index 9b78c95..cbd975b 100644 --- a/prolog/problems/family_relations/sister_2/en.py +++ b/prolog/problems/family_relations/sister_2/en.py @@ -2,18 +2,81 @@ name = 'sister/2' slug = 'the sister relation' description = '''\ -<p><code>sister(X, Y)</code>: <code>X</code> is a sister of <code>Y</code>.</p> +<p><code>sister(X, Y)</code>: <code>X</code> is a (half)sister of <code>Y</code>.</p> <pre> ?- sister(vanessa, X). X = patricia. -</pre>''' +</pre> +<p><a target="_blank" href="[%@resource famrel.svg%]">Family trees</a> are +described with predicates <code>parent/2</code>, <code>male/1</code>, and +<code>female/1</code>.</p> +''' + +plan = [ + '''\ +<p><img src="[%@resource Prolog_sister_01.svg%]" alt="A sister is female and has a common parent with Y." /></p>''', + '''\ +<p>If <code>X</code> is female and if <code>X</code> and <code>Y</code> share a common parent +then <code>X</code> is a sister of <code>Y</code>.</p>''', + '''\ +<p><img src="[%@resource Prolog_sister_02.svg%]" alt="Sister X is female and has +at least one parent in common with Y." /></p>''', +] hint = { - 'x_y_must_be_different': '''\ -<p>What if <code>X</code> and <code>Y</code> are the same person? Try the -following query:</p> + 'x_y_must_be_different': [{'message': '''\ +<p><img src="[%@resource Prolog_sister_04.svg%]" /></p> +<p>What if <code>X</code> and <code>Y</code> are the same person? Try the following query:</p> <pre> ?- sister(sally, Y). -</pre> +</pre>''', 'linkText': 'How can I check that <code>X</code> and <code>Y</code> are different?'}, +'''\ +<p>Using the operator <code>\==</code> I can check that <code>X</code> and <code>Y</code> are different. +For example: <code>X \== Y</code></p> +'''], + + 'x_must_be_female': '''\ +<p><img src="[%@resource Prolog_sister_03.svg%]" /></p> +<p>A sister is usually female.</p> +''', + + 'y_can_be_of_any_gender': '''\ +<p><code>Y</code> can actually be of <em>any</em> gender.</p> +''', + + 'neq+_instead_of_neq': '''\ +<p>Use the operator \== instead of operators \= or =\=. It succeeds when the two operands are not the same, +while \= succeeds if the operands <em>cannot be made</em> the same (cannot be unified), and =\= checks for +arithmetic inequality and in this case both operands should be immediately arithmetically computable.</p> +''', + + 'common_parent_needed': '''\ +<p><img src="[%@resource Prolog_sister_05.svg%]" /></p> +<p>It would make sense if <code>X</code> and <code>Y</code> have at least one parent in common.</p> +''', + + 'neq_used_too_early': '''\ +<p>Did you use the operator <code>\==</code> too early?</p> +<p>Try moving it more towards the end of the rule. The problem is probably that the variables +you are comparing don't yet have values assigned to them and are therefore different by default. +Prolog doesn't check whether they become equal <em>later</em>, it only checks whether they're +equal or not at the moment of comparison.</p> +<p>Or maybe you're simply comparing the wrong two variables?</p> +''', + + 'predicate_always_false': '''\ +<p>It seems your predicate is <em>always</em> "false". Did you give it the correct name, +or is it perhaps misspelled?</p> +<p>If the name is correct, check whether something else is misspelled, perhaps there is a full stop instead of +a comma or vice versa, or maybe you typed a variable name in lowercase?</p> +<p>It is, of course, also possible that your conditions are too restrictive, or even impossible to satisfy +(as would be, for example, the condition that <code>X</code> is both a parent and a sister of <code>Y</code>, or +something similarly impossible).</p> +''', + + 'final_hint': '''\ +<p>In this exercise you used the \== operator. It succeeds if its two operands are not the same +<em>at the moment</em> of comparison. If you put this goal at the start of your rule, it will +not work as expected. (Go ahead, try and see what happens!)</p> ''', } |