3 files changed, 0 insertions, 152 deletions
diff --git a/prolog/problems/lists_advanced/count_3/common.py b/prolog/problems/lists_advanced/count_3/common.py
deleted file mode 100644
index 7d66d6b..0000000
--- a/prolog/problems/lists_advanced/count_3/common.py
+++ /dev/null
@@ -1,96 +0,0 @@
-from operator import itemgetter
-import socket
-
-import prolog.engine
-import prolog.util
-from server.hints import Hint, HintPopup
-
-id = 120
-number = 110
-visible = False
-facts = None
-
-solution = '''\
-count(_, [], 0).
-count(X, [X|T], N) :-
-  count(X, T, NT),
-  N is NT + 1.
-count(X, [Y|T], NT) :-
-  X \== Y,
-  count(X, T, NT).
-'''
-
-hint_type = {
-    'eq_instead_of_equ_markup': HintPopup('eq_instead_of_equ_markup'),
-    'eq_instead_of_equ': Hint('eq_instead_of_equ'),
-    'predicate_always_false': Hint('predicate_always_false'),
-    'base_case': Hint('base_case'),
-    'recursive_case': Hint('recursive_case'),
-    'timeout': Hint('timeout'),
-}
-
-test_cases = [
-    ('count(a, [], X)',
-        [{'X': '0'}]),
-    ('count(r, [a, r, b, c, r], X)',
-        [{'X': '2'}]),
-    ('count(l, [l, l, l, 1, 2, 3], X)',
-        [{'X': '3'}]),
-    ('count(z, [a, b, c, z, z], X)',
-        [{'X': '2'}]),
-]
-
-def test(code, aux_code):
-    n_correct = 0
-    engine_id = None
-    try:
-        engine_id, output = prolog.engine.create(code=code+aux_code, timeout=1.0)
-        if engine_id is not None and 'error' not in map(itemgetter(0), output):
-            # Engine successfully created, and no syntax error in program.
-            for query, answers in test_cases:
-                if prolog.engine.check_answers(engine_id, query=query, answers=answers, timeout=1.0):
-                    n_correct += 1
-    except socket.timeout:
-        pass
-    finally:
-        if engine_id:
-            prolog.engine.destroy(engine_id)
-
-    hints = [{'id': 'test_results', 'args': {'passed': n_correct, 'total': len(test_cases)}}]
-    return n_correct, len(test_cases), hints
-
-def hint(code, aux_code):
-    tokens = prolog.util.tokenize(code)
-
-    try:
-        engine_id, output = prolog.engine.create(code=code+aux_code, timeout=1.0)
-
-        # strict equality testing instead of simple matching
-        # this is usually (but not necessarily) wrong
-        targets = [prolog.util.Token('EQ', '==')]
-        marks = [(t.pos, t.pos + len(t.val)) for t in tokens if t in targets]
-        if marks:
-            return [{'id': 'eq_instead_of_equ_markup', 'start': m[0], 'end': m[1]} for m in marks] + \
-                   [{'id': 'eq_instead_of_equ'}]
-
-        # missing/failed base case
-        if not prolog.engine.ask_truthTO(engine_id, 'count(42, [], 0)'):
-            return [{'id': 'base_case'}]
-
-        # target predicate seems to always be false
-        if not prolog.engine.ask_truthTO(engine_id, 'count(_, _, _)'):
-            return [{'id': 'predicate_always_false'}]
-
-        # base case works, the recursive doesn't (but it doesn't timeout)
-        # this may be left as the last, most generic hint
-        if not prolog.engine.ask_truth(engine_id, 'count(42, [2, 41, 42, -22, 42], 2)'):
-            return [{'id': 'recursive_case'}]
-
-    except socket.timeout as ex:
-        return [{'id': 'timeout'}]
-
-    finally:
-        if engine_id:
-            prolog.engine.destroy(engine_id)
-
-    return []
diff --git a/prolog/problems/lists_advanced/count_3/en.py b/prolog/problems/lists_advanced/count_3/en.py
deleted file mode 100644
index 481fd1c..0000000
--- a/prolog/problems/lists_advanced/count_3/en.py
+++ /dev/null
@@ -1,11 +0,0 @@
-name = 'count/3'
-slug = 'find the number of occurrences of an element in list'
-
-description = '''\
-<p><code>count(X, L, N)</code>: <code>N</code> is the number of times the element <code>X</code> appears in the list <code>L</code>.</p>
-<pre>
-?- count(1, [1,2,1,3,1], N).
-  N = 3.
-</pre>'''
-
-hint = {}
diff --git a/prolog/problems/lists_advanced/count_3/sl.py b/prolog/problems/lists_advanced/count_3/sl.py
deleted file mode 100644
index 1e3f5d2..0000000
--- a/prolog/problems/lists_advanced/count_3/sl.py
+++ /dev/null
@@ -1,45 +0,0 @@
-name = 'count/3'
-slug = 'Preštej kolikokrat se element pojavi v seznamu'
-
-description = '''\
-<p><code>count(X, L, N)</code>: <code>N</code> je število kolikokrat se element <code>X</code> pojavi v seznamu <code>L</code>.</p>
-<pre>
-?- count(1, [1,2,1,3,1], N).
-  N = 3.
-</pre>'''
-
-hint = {
-    'eq_instead_of_equ': '''\
-<p>Operator <code>==</code> je strožji od operatorja <code>=</code> v smislu, da je za slednjega dovolj,
-da elementa lahko naredi enaka (unifikacija). Morda z uporabo <code>=</code> narediš predikat
-<code>memb/2</code> delujoč tudi v kakšni drugi smeri.</p>
-<p>Seveda pa lahko nalogo rešiš brez obeh omenjenih operatorjev, spomni se, da lahko unifikacijo narediš
-implicitno že kar v argumentih predikata (glavi stavka).</p>
-''',
-
-    'eq_instead_of_equ_markup': '''\
-<p>Morda bi bil bolj primeren operator za unifikacijo (=)?</p>
-''',
-
-    'base_case': '''\
-<p>Si pomislil na robni pogoj? Kaj je najbolj enostaven primer, ko je element v seznamu?
-Do katerega elementa najlažje prideš?</p>
-''',
-
-    'recursive_case': '''\
-<p>Robni primer deluje. Kaj pa rekurzivni, splošni, primer?</p>
-''',
-
-    'predicate_always_false': '''\
-<p>Vse kaže, da tvoj predikat vedno vrne "false". Si mu dal pravilno ime, si se morda pri imenu zatipkal?</p>
-<p>Če je ime pravilno, se morda splača preveriti tudi, če se nisi zatipkal kje drugje,
-je morda kakšna pika namesto vejice ali obratno, morda kakšna spremenljivka z malo začetnico?</p>
-<p>Možno je seveda tudi, da so tvoji pogoji prestrogi ali celo nemogoči (kot bi bila npr. zahteva,
-da je <code>X</code> hkrati starš in sestra od <code>Y</code> ali kaj podobno zlobnega).</p>
-''',
-
-    'timeout': '''\
-<p>Je morda na delu potencialno neskončna rekurzija? Kako se bo ustavila?</p>
-<p>Morda pa je kriv tudi manjkajoč, neustrezen ali preprosto nekompatibilen (s splošnim primerom) robni pogoj?</p>
-''',
-}