prolog/problems/clp_r/megabytes_2/common.py


1
2
3
4
5
6
7
8
9
10
11

# coding=utf-8

id = 160
group = 'clp_r'
number = 65
visible = True
facts = None

solution = '''\
megabytes(SI, IEC) :-
    { SI * 2^20 = IEC * 10^6 }.'''