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# coding=utf-8
from operator import itemgetter
import socket
import prolog.engine
import prolog.util
from server.hints import Hint
import server.problems
id = 94
number = 1
visible = True
facts = 'family_relations'
solution = '''\
mother(X, Y) :-
parent(X, Y),
female(X).
'''
hint_type = {
'or_instead_of_and': Hint('or_instead_of_and'),
'or_instead_of_and_two_rules': Hint('or_instead_of_and_two_rules'),
'x_must_be_female': Hint('x_must_be_female'),
'x_must_be_parent': Hint('x_must_be_parent'),
'y_can_be_of_any_gender': Hint('y_can_be_of_any_gender'),
'y_need_not_be_parent': Hint('y_need_not_be_parent'),
}
test_cases = [
('mother(X, _)',
[{'X': 'ana'}, {'X': 'elaine'}, {'X': 'estelle'}, {'X': 'helen'},
{'X': 'jill'}, {'X': 'joanne'}, {'X': 'margaret'}, {'X': 'nevia'},
{'X': 'patricia'}, {'X': 'sally'}, {'X': 'tina'}, {'X': 'vanessa'}]),
('mother(_, X)',
[{'X': 'aleksander'}, {'X': 'alessandro'}, {'X': 'andrew'},
{'X': 'anna'}, {'X': 'daniela'}, {'X': 'george'}, {'X': 'jerry'},
{'X': 'joanne'}, {'X': 'john'}, {'X': 'kramer'}, {'X': 'luana'},
{'X': 'melanie'}, {'X': 'nevia'}, {'X': 'steve'}, {'X': 'susan'},
{'X': 'william'}]),
('mother(joanne, X)',
[{'X': 'steve'}]),
]
def test(code, aux_code):
n_correct = 0
engine_id = None
try:
engine_id, output = prolog.engine.create(code=code+aux_code, timeout=1.0)
if engine_id is not None and 'error' not in map(itemgetter(0), output):
# Engine successfully created, and no syntax error in program.
for query, answers in test_cases:
if prolog.engine.check_answers(engine_id, query=query, answers=answers, timeout=1.0):
n_correct += 1
finally:
if engine_id:
prolog.engine.destroy(engine_id)
hints = [{'id': 'test_results', 'args': {'passed': n_correct, 'total': len(test_cases)}}]
return n_correct, len(test_cases), hints
def hint(code, aux_code):
tokens = prolog.util.tokenize(code)
try:
engine_id, output = prolog.engine.create(code=code+aux_code, timeout=1.0)
# OR (;) instead of AND (,)
# this hint has to be before the next two
# as otherwise those two would always override it
# and not convey the same (amount of) help/information
# warning: due to speed considerations this (50) is knowledge base dependent
# independent: findall(_, (parent(X, Y) ; female(X)), L2)
if prolog.util.Token('SEMI', ';') in tokens and prolog.engine.ask_truth(engine_id,
'findall(_, mother(X, Y), L), length(L, 50)'):
return [{'id': 'or_instead_of_and'}]
# OR instead of AND written with two rules, namely:
# (r1) mother(X, Y):- female(X). (r2) mother(X, Y):- parent(X, Y).
if prolog.engine.ask_truth(engine_id,
'findall(_, mother(X, Y), L), length(L, 50)'):
return [{'id': 'or_instead_of_and_two_rules'}]
# X must be female
if prolog.engine.ask_truth(engine_id, 'male(X), mother(X, _)'):
return [{'id': 'x_must_be_female'}]
# X must be a parent
if prolog.engine.ask_truth(engine_id,
'mother(X, _), \+ parent(X, _)'):
return [{'id': 'x_must_be_parent'}]
# Y can be of any gender, incl. male
if prolog.engine.ask_one(engine_id,
'mother(_, Y), male(Y)') == 'false':
return [{'id': 'y_can_be_of_any_gender'}]
# Y does not necessarily need to be a parent
if prolog.engine.ask_one(engine_id,
'mother(_, Y), \+ parent(Y, _)') == 'false':
return [{'id': 'y_need_not_be_parent'}]
except socket.timeout as ex:
pass
finally:
if engine_id:
prolog.engine.destroy(engine_id)
return None
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